From 26a02a3f7165b2d4f3a1ccbef254e97daa88c81f Mon Sep 17 00:00:00 2001
From: Sabrina Chowdhury <sabrina.chowdhury29@gmail.com>
Date: Sat, 28 Aug 2021 04:02:03 +0200
Subject: [PATCH] update

---
 docs/electronics/Motors.md | 4 +---
 1 file changed, 1 insertion(+), 3 deletions(-)

diff --git a/docs/electronics/Motors.md b/docs/electronics/Motors.md
index 1a5e3fc..c419007 100644
--- a/docs/electronics/Motors.md
+++ b/docs/electronics/Motors.md
@@ -132,9 +132,7 @@ The most technical ways of choosing the stepper motors are mentioned in [Motor S
 
 - The inductance of the motor affects how fast the stepper motor driver can drive the motor before the torque drops off. If we temporarily ignore the back emf due to rotation and the rated motor voltage is much less than the driver supply voltage, then the maximum revs/second before torque drops off is:
 
-> ***revs_per_second = (2 * supply_voltage)/(steps_per_rev * pi * inductance * current)***
-
-![equation](https://latex.codecogs.com/svg.image?revs/second&space;=&space;2&space;\times&space;V_{Supply}&space;/&space;(steps/rev&space;\times&space;&space;pi&space;\times&space;&space;inductance&space;\times&space;&space;current))
+ > ![equation](https://latex.codecogs.com/svg.image?revs/second%20=%202%20%5Ctimes%20V_%7BSupply%7D%20/%20(steps/rev%20%5Ctimes%20%20pi%20%5Ctimes%20%20inductance%20%5Ctimes%20%20current))
 
 - If the motor is driving a GT2 belt via a pulley, this gives the maximum speed in mm/sec as:
 
-- 
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